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x^2-3x+11=x+1
We move all terms to the left:
x^2-3x+11-(x+1)=0
We get rid of parentheses
x^2-3x-x-1+11=0
We add all the numbers together, and all the variables
x^2-4x+10=0
a = 1; b = -4; c = +10;
Δ = b2-4ac
Δ = -42-4·1·10
Δ = -24
Delta is less than zero, so there is no solution for the equation
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